-9x^2+18x+135=0

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Solution for -9x^2+18x+135=0 equation:



-9x^2+18x+135=0
a = -9; b = 18; c = +135;
Δ = b2-4ac
Δ = 182-4·(-9)·135
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-72}{2*-9}=\frac{-90}{-18} =+5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+72}{2*-9}=\frac{54}{-18} =-3 $

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